Let ω be the circumcircle of right-angled triangle ABC (∠A = 90◦). Tangent to ω at point A intersects the line BC in point P. Suppose that M is the midpoint of (the smaller) arc AB, and PM intersects ω for the second time in Q. Tangent to ω at point Q intersects AC in K. Prove that ∠PKC = 90◦.
Proposed by Davood Vakili.